A 59kg child starting from rest slides down a water slide with a vertical height of 5.0m. what is the child's speed halfway down the slide's vertical distance

EP (potential energy) = mgy - > (59) (9.8) (-5) = - 2,891

EP + EK (kinetic energy) = 0; but rearranging it for EK makes it EK = - EP, such that EK = 2891 when plugged in.

EK = 0.5mv^2, but can also be v = sqrt (2EK/m).

Plugging that in for sqrt ((2 * 2891) / 59), we get 9.9 m/s^2 with respect to significant figures.