Ask Question
17 November, 03:52

When a water gun is fired while being held horizontally at a height of 1.00 m above ground level, the water travels a horizontal distance of 5.00 m. a child, who is holding the same gun in a horizontal position, is also sliding down a 45.0° incline at a constant speed of 2.00 m/s. if the child fires the gun when it is 1.00 m above the ground and the water takes 0.329 s to reach the ground, how far will the water travel horizontally?

+5
Answers (1)
  1. 17 November, 05:04
    0
    Refer to the diagrams shown below.

    Neglect air resistance.

    Case A.

    Let t = the time of flight.

    Then for horizontal travel,

    t = (5 m) / (u m/s) = 5/u s

    For vertical travel,

    1.0 m = (1/2) * (9.8 m/s²) * (5/u s) ²

    5/u = √ (1/4.9) = 0.4518

    u = 11.0668 m/s

    Case B.

    There are two contributions to the horizontal velocity

    (i) 11.0668 m/s

    (ii) (2 m/s) * cos (45) = 1.4142 m/s

    The total horizontal velocity is

    11.0668 + 1.4142 = 12.481 m/s

    Because the time of flight is 0.329 s, the horizontal distance traveled is

    d = (12.481 m/s) * (0.329 s) = 4.106 m

    Answer: The horizontal distance traveled is 4.11 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “When a water gun is fired while being held horizontally at a height of 1.00 m above ground level, the water travels a horizontal distance ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers