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17 August, 18:03

A 0.145 kg baseball is thrown from a platform above the ground at a 10 m/s. the ball is moving 15 m/s when it strikes the ground. from what height above the ground was the ball thrown? 6 m 10 m 1 m 5 m

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  1. 17 August, 21:31
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    V^2 = v0^2 + 2gh

    2gh = v^2 - v0^2

    h = (v^2 - v0^2) / 2g

    h = ((15 m/s) ^2 - (10 m/s) ^2) / 2*9.81 m/s^2

    h = (225 m^2/s^2 - 100 m^2/s^2) / 19.62 m/s^2

    h = 125 m^2/s^2/19.62 m/s^2

    h = 6.37 m ≈ 6 m
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