Without the wheels, a bicycle frame has a mass of 8.47 kg. each of the wheels can be roughly modeled as a uniform solid disk with a mass of 0.820 kg and a radius of 0.343 m. find the kinetic energy of the whole bicycle when it is moving forward at 3.55 m/s.

Refer to the diagram shown below.

Given:

m₁ = 8.47 kg, the mass of the bicycle frame

m₂ = 0.82 kg. the mass of each wheel

r = 0.343 m, the radius of each wheel

v = 3.55 m/s, forward velocity.

The moment of inertia of each wheel is

I = (1/2) * m₂*r² = 0.5 * (0.82 kg) * (0.343 m) ² = 0.048224 kg-m²

The angular velocity of each wheel is

ω = (3.55 m/s) / (0.343 m) = 10.35 rad/s

The kinetic energy of the bicycle is

KE = (1/2) * m₁*v² + 2 * (1/2) * I*ω²)

= 0.5 * (8.47 kg) * (3.55 m/s) ² + (0.048224 kg-m²) * (10.35 rad/s) ²

= 58.5375 J

Answer: 58.54 J