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24 April, 08:14

A hockey puck of mass 0.450 kg is sliding across the ice. the puck is initially moving at 28 m/sec. however, because of the frictional force between the puck and the ice, the motion of the puck is stopped in 15.8 seconds. determine the magnitude of the frictional force.

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  1. 24 April, 12:10
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    Impulse is known as change in momentum, I = Change in Momentum Momentum M = m x V

    Initial Momentum = m x Vi; Final Momentum = m x Vf

    Change in Momentum = (m x Vf) - (m x Vi) = m (Vf - Vi)

    Final velocity will be 0, So Change in Momentum = - mVi

    Impulse = F x t = > F x t = - m x Vi = > F = ( - m x Vi) / t

    => F = ( - 0.450 x 28) / 15.8 = - 0.79N

    So the magnitude of the frictional force is 0.79N
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