Radio signals travel at a rate of 3 * 108 meters per second. how many seconds would it take for a radio signal to travel from a satellite to the surface of earth if the satellite is orbiting at a height of 9.6 * 106 meters? (hint: time is distance divided by speed.)

3.2x10^-2 seconds (0.032 seconds)

This is a simple matter of division. I also suspect it's an exercise in scientific notation, so here is how you divide in scientific notation:

9.6 x 10^6 m / 3x10^8 m/s

First, divide the significands like you would normally.

9.6 / 3 = 3.2

And subtract the exponent. So

6 - 8 = - 2

So the answer is 3.2 x 10^-2

And since the significand is less than 10 and at least 1, we don't need to normalize it.

So it takes 3.2x10^-2 seconds for the radio signal to reach the satellite.