You weigh 730 n. what would you weigh if the earth were six times as massive as it is and its radius were three times its present value? answer in units of n.

By definition we have to:

F = G * M * m / r ^ 2

where,

F = Gravitational force

G = Gravitational constant. (6.67 x 10 ^ - 11 Nm ^ 2 / kg ^ 2)

M = mass of the earth

m = mass of the object

r = radius of the earth

If the earth were six times as massive as it is:

M = 6M

radius were three times its present value:

r = 3r

We have the equation is:

F = G * (6M) * m / (3r) ^ 2 = (6/9) * (G * M * m / r ^ 2) = (2/3) * (G * M * m / r ^ 2)

Therefore the weight will be

(2/3) * F = (2/3) * (730) = 487N

answer

Your weight will be 487N