A robot probe drops a camera off the rim of a 239 m high cliff on mars, where the free-fall acceleration is - 3.7 m/s2.

a. find the velocity with which the camera hits the ground.

b. find the time required for it to hit the ground.

a. We can find the velocity when the camera hits the ground. v^2 = (v0) ^2 + 2ay = 0 + 2ay v = sqrt{ 2ay } v = sqrt{ (2) (3.7 m/s^2) (239 m) } v = 42 m/s The camera hits the ground with a velocity of 42 m/s b. We can find the time it takes for the camera to hit the ground. y = (1/2) a t^2 t^2 = 2y / a t = sqrt{ 2y / a } t = sqrt{ (2) (239 m) / 3.7 m/s^2 } t = 11.4 seconds

It takes 11.4 seconds for the camera to hit the ground.