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6 November, 03:04

Imagine riding On a merry-go-round at the center. As you walk to the outer edge, the merry-go-round slows in order to conserve angular momentum. True or false?

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  1. 6 November, 05:54
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    Answer: True

    Explanation:

    When riding at the center, the angular momentum is

    Iω²

    where I = rotational inertia

    ω = angular velocity.

    When you move away from the center to a radius r, you add to the rotational inertia by mr², where m is your mass.

    The new rotational inertia becomes I + mr².

    If the new angular velocity is ω₁. then

    (I + mr²) ω₁² = Iω²

    Therefore

    ω₁² = Iω² / (I + mr²)

    Therefore ω₁ < ω in order to conserve angular momentum.
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