Ask Question
14 May, 06:42

During fuel burn, the vertically launched Terrier-Sandhawk rocket had an acceleration of 300m/s^2 (about 30 times free-fall acceleration called 30g). The fuel burned for 8.0 s. Find the height of the Terrier-Sandhawk rocket at the end of fuel burn.

+1
Answers (1)
  1. 14 May, 07:59
    0
    Initial launch velocity, u = 0

    Acceleration, a = 300 m/s²

    Duration, t = 8.0 s

    The distance traveled is

    h = ut + (1/2) * a*t²

    = (0 m/s) * (8 s) + 0.5 * (300 m/s²) * (8 s) ²

    = 9600 m

    Answer: 9600 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “During fuel burn, the vertically launched Terrier-Sandhawk rocket had an acceleration of 300m/s^2 (about 30 times free-fall acceleration ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers