A lead mass is heated and placed in a foam cup calorimeter containing 50.0 ml of water at 18.0°c. the water reaches a temperature of 20.0°c. how much heat was released by the lead?

Assuming that there is no heat loss, and the cup is perfectly insulated, all of the energy lost by the lead will be absorbed by the water.

The heat absorbed is given by:

Energy = mass * specific heat capacity * change in temperature

The specific heat capacity of water is 4.18 joules per gram.

In order to compute the mass, we will use the fact that the density of water is one gram per milliliter. Therefore, the mass of water is 50 grams.

Now,

Q = 50 * 4.18 * (20 - 18)

Q = 418 J

418 Joules of energy were released by the lead.