How much heat is absorbed by a 43g iron skillet when its temperature rises from 5oC to 25oC?

381.84 that how much heat absorbs

This problem is described by the formula q=mc*deltaT

q is heat, m is mass, c is specific heat capacity (which varies based on substance, I googled the value for iron, which gave me 0.444 J/g*°C) and deltaT is temperature change.

Temperature change can be solved for by subtracting the initial temperature from the final, Tf-Ti, so 25-5 = 20 °C, which gives us everything we need to solve for q.

q = 43 g * 0.444 J/g*°C * 20 °C

q = 381.84 J of heat absorbed