The average intensity of sunlight at the top of the earth's atmosphere in 1390 w/m2. what is the maximum energy that a 34-m x 46-m solar panel could collect in 2.0 hours in this sunlight

Panel surface area = 34m*46m=1,564m^2

total power = 1564m^2*1390w/m^2

=2173960watts

now you must calculate total energy.

Energy = power*Time

However time must be in seconds so we multiply 2hrs*60min*60s=7200seconds

7200s*2173960w = 15,652,512,000 joules of energy