If the organ pipe is cut in half, what is the new fundamental frequency? if the organ pipe is cut in half, what is the new fundamental frequency? 4f0 2f0 f0 f0/2 f0/4

The frequency for a fundamental pipe is given as:

f = v/4L

L is equal to the length of the pipe

Since L = Lo/2 where Lo is the original length of the pipe, the new frequency would be:

f = (v/4) / (Lo/2)

f = 2 (v/4Lo)

Since v/4Lo = fo, therefore:

f = 2 fo