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4 April, 09:33

A 0.300 kg ball is thrown vertically upward with an initial speed of 17.0 m/s. part a what is the maximum height reached by the ball?

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  1. 4 April, 13:11
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    1/2 mv^2 = mgh, all of the initial kinetic energy is converted to potential energy

    So (since you can see how 'm' divides out):

    (0.5) v^2 = gh, g = acceleration of gravity

    (0.5) (20.0) ^2 = (9.8) h

    200 = 9.8h

    h=20.4 m
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