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21 January, 20:32

What s the value of work done on an object when a 10-newton force moves it 30meters and the angle between the force and the displacement at 25 degrees

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  1. 21 January, 21:16
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    Horizontal component = cos (25) * 10 = 9.06 N

    work done = 9.06*30 = 271.9 J
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