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11 July, 18:18

A kid moving 3.18 m/s jumps on a slip and slide (Uk=0.0751). How far has he slid when his velocity is reduced to 2.00 m/s?

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  1. 11 July, 18:40
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    F=ma (Newton's second law of motion).

    Then,

    a = F/m = Uk*mg/m = Uk*g = 0.0751*9.81 = 0.737 m/s^2 (should be negative since a deceleration is expected).

    v = Sqrt (u^2-2ad), Where v = final velocity, u=initial velocity, a = acceleration, d = distance moved.

    Therefore,

    v^2-u^2 = - 2ad = > d = (v^2-u^2) / - 2a = (2^2-3.18^2) / - 2*0.737 = 4.15 m
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