A rocket, weighing 43576 N, has an engine that provides an upward force of 11918 N. It reaches a maximum speed of 713 m/s. For how much time must the engine burn during the launch in order to reach this speed? Call up positive.

Answer: 266.0 s ≈ 4.4 min

Explanation:

1) Data

Wr = 43,576 N

F = 11,918 N

V = 713 m/s

t = ?

2) Principles and formulas

Impulse and conservation of momentum

I = F. t = Δp

Δp = mΔv

3) Solution

m = Wr / g = 43,576N / 9.8 m/s^2 = 4,446.5 kg

Δp = mΔv = > 4,446.5 kg * 713 m/s = 3,170,354,5 N*s

I = F. t = Δp = > t = Δp / F = 3,710,354.5 N*s / 11,918N = 266.0 s

t = 266.0 s ≈ 4.4 min