A bat hits a 0.150 kg baseball for 0.0880s. The balls velocity changes from 41.0 m/s left to 37.0 m/s right. How much force was applied to the ball? Unit = N

Question

Physics

Dale

21 August, 13:09

A bat hits a 0.150 kg baseball for 0.0880s. The balls velocity changes from 41.0 m/s left to 37.0 m/s right. How much force was applied to the ball? Unit = N

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Answers (1)

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Niko Owen · Answer 1

From Newton's second law of motion,

F=ma

Where, F = applied force, m = mass (=0.15 kg), a = acceleration.

a = Δv/t, Δv = Change in velocity, t = time

Therefore

a = (41-37) / 0.088 = 45.45 m/s^2

Then,

F = 0.15*45.45 = 6.82 N