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20 July, 07:59

A worker pushes a wheelbarrow with a force of 40 n over a level distance of 6.0 m. if a frictional force of 24 n acts on the wheelbarrow in a direction opposite to that of the worker, what net work is done on the wheelbarrow?

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  1. 20 July, 08:16
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    Net work done = 40*6 - 24 * 6

    =96 j
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