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16 September, 19:23

Protons in an atomic nucleus are typically 10-15 m apart. what is the electric force (in n) of repulsion between nuclear protons? (enter the magnitude.)

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  1. 16 September, 21:00
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    The electric force is given by:

    F = [ k * (q1) * (q2) ] / d^2

    F = Electric force

    k = Coulomb's constant

    q1 = Charge of one proton

    q2 = Charge of second proton

    d = Distance between centers of mass

    Values:

    F = unknown

    k = 8.98E 9 N-m^2/C^2

    q1 = 1.6E-19

    q2 = 1.6E-19

    d = 1.0E-15 m

    Insert values into F = [ k * (q1) * (q2) ] / d^2

    F = [ (8.98E 9 N-m^2/C^2) * (1.6E-19) * (1.6E-19) ] / (1.0E-15 m) ^2

    F = 229.888 N

    answer

    the electric force of repulsion between nuclear protons is 229.888 N
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