A 66-kg skier starts from rest at the top of a 1200-mlong trail which drops a total of 230 m from top to bottom. at the bottom, the skier is moving 11.0 m/s. how much energy was dissipated by friction?

Energy dissipated by friction is E Initial Ei=mgh Final Ef=1/2 mv^2 then subtracted Ef-Ei, Î"E = 0 m g h - - E â€" 1/2 m v² = 0 66 (9.8) (250) - E - ½ (66) (14) ² = 0 E = (9.8) (250) â€" ((14) ^2) / 2 E = 155.232kJ