Ask Question
23 May, 08:22

A 66-kg skier starts from rest at the top of a 1200-mlong trail which drops a total of 230 m from top to bottom. at the bottom, the skier is moving 11.0 m/s. how much energy was dissipated by friction?

+3
Answers (1)
  1. 23 May, 08:44
    0
    Energy dissipated by friction is E Initial Ei=mgh Final Ef=1/2 mv^2 then subtracted Ef-Ei, Î"E = 0 m g h - - E â€" 1/2 m v² = 0 66 (9.8) (250) - E - ½ (66) (14) ² = 0 E = (9.8) (250) â€" ((14) ^2) / 2 E = 155.232kJ
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 66-kg skier starts from rest at the top of a 1200-mlong trail which drops a total of 230 m from top to bottom. at the bottom, the skier ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers