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18 October, 12:49

How much would you have to raise the temperature of a copper wire (originally at 20? c) to increase its resistance by 18 %? the temperature coefficient of resistivity of copper is 0.0068 (? c) ?1?

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  1. 18 October, 16:44
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    The equation for how temperature changes the resistance R is:

    R=R₀ (1+α (T-T₀)), where R₀ is the resistance at T₀=20°C, T is the temperature for which we want to calculate the resistance and α is the temperature coefficient for resistance.

    The resistance of the copper wire increases by 18% or by 0.18, so the new value for the resistance is R=1.18*R₀.

    T₀=20°C

    =0.0068

    R=1.18*R₀

    Now we need to input that into the equation for resistance change and solve for temperature T.

    1.18R₀=R₀ (1+α (T-20)), R₀ cancels out,

    1.18=1+α (T-20),

    1.18-1=α (T-20), we divide by α,

    0.18/α=T-20, we put 20 on the left side,

    26.47+20=T

    T=46.47°C

    So the temperature on which the resistance of copper wire will increase by 18% is T=46.47°C.
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