Ask Question
21 July, 22:02

How much energy would be needed to raise the temperature of 40 liters of water (about the total water volume in an adult man) 2 degrees celsius?

+5
Answers (1)
  1. 22 July, 00:21
    0
    40 liters of water = 40 * (10³ cm³/L) = 4 x 10⁴ cm³

    The density of water is 1 g/cm³, therefore 40 liters of water has a mass of

    m = (4 x 10⁴ cm³) * (1 g/cm³) = 4 x 10⁴ g

    The specific heat of water is c = 4.184 J / (g - °C).

    For a temperature increase of ΔT = 2 °C, the thermal energy required is

    Q = m*c*ΔT

    = (4 x 10⁴ g) * (4.184 J / (g-°C)) * (2 °C)

    = 334,720 J = 334.72 kJ

    Answer: 334.7 kJ (nearest tenth)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How much energy would be needed to raise the temperature of 40 liters of water (about the total water volume in an adult man) 2 degrees ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers