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27 July, 19:34

1. A 700kg racecar slowed from 30m/s to 15 m/s. What was its change in Momentum? 2. If the car in the above problem took 5 seconds to slow down from 30m/s to 15 m/s. a. What is the impulse? b. What was the average force applied by the brakes?

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  1. 27 July, 22:20
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    1. The change in momentum follows the formula:

    Change in Momentum = mΔv,

    where m is the mass and v is the velocity

    Change in momentum = (700 kg) (15 m/s - 30 m/s) = - 10,500 kg·m/s

    2. For this problem, the formula for impulse, J, is

    J = FΔt

    Before answering part a, we answer for part b first.

    Part B.

    F = ma

    where

    a = Δv/t = (15 - 30) / 5 = - 1 m/s²

    So,

    F = (700 kg) (-1 m/s²) = - 700 N

    Part A.

    J = (-700 N) (5 s) = - 3,500 N·s
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