A tuning fork vibrating at a frequency of 512hz is held over the top of the jar filled with water and filled with a tap at the bottom. If the jar is 60cm tall and the speed of sound is 350ms-1, determine 1st and 2nd resonance.

Question

Physics

Eden Stout

4 October, 05:59

A tuning fork vibrating at a frequency of 512hz is held over the top of the jar filled with water and filled with a tap at the bottom. If the jar is 60cm tall and the speed of sound is 350ms-1, determine 1st and 2nd resonance.

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Meredith Gardner · Answer 1

Frequency of tuning fork f = 512 Hz

Speed of sound V = 350ms-1

Height of the jar = 60 cm = 0.06 m

Velocity = wavelength x frequency = > V = lambda x f = > lambda = V / f = 350 / 512

Wavelength = 350 / 512 = 0.684

1st resonance at = lambda / 4 = 0.684 / 4 = 0.171 = 17 cm

2nd resonance at = (3 x lambda) / 4 = (3 x 0.684) / 4 = 0.513 = 51 cm