An airplane flies eastward and always accelerates at a constant rate. at one position along its path it has a velocity of 26.3 m/s, it then flies a further distance of 48100 m and afterwards its velocity is 41.9 m/s. find the airplane/'s acceleration and calculate how much time elapses while the airplane covers those 48100 m.

We will use the formula / equation to determined the time.

Distance = ½ * (vi + vf) * t

48100 = ½ * (26.3 + 41.9) * t

t = 48100 : 34.1 = 1410.557185 seconds

We will use the formula / equation to determined the acceleration.

vf = vi + a * t

41.9 = 26.3 + a * 1410.557185

a = (41.9 - 26.3) : 1410.557185 = 0.011059459 m/s^2

We will use the formula / equation to determined the acceleration.

vf^2 = vi^2 + 2 * a * d

41.9^1 = 26.3^2 + 2 * a * 48100

a = (41.9^2 - 26.3^2) : 96200 = 0. 011059459 m/s^2

Since both answers are the same, I believe the acceleration is correct.