A student walks 5.00 m at an angle of 53.0° then walks another 8.00 m at angle of 130°. what is the magnitude of the student's final displacement?

This question can easily be answered using a scientific calculator via complex mode using the form r∠α wherein r is the magnitude and α is the angle. So, incorporating vector addition through scientific calculator:

5∠53° + 8∠130 = 10.34∠101.9°

Therefore, the student's displacement is 10.34 m, 101.9°. In other words, the student is heading 78.1° (180 - 101.9 = 78.1) south of east.