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6 January, 08:51

A man jogs at a speed of 1.6 m/s. His dog

waits 1.8 s and then takes off running at a

speed of 2.7 m/s to catch the man.

How far will they have each traveled when

the dog catches up with the man?

Answer in units of m.

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Answers (1)
  1. 6 January, 12:12
    0
    I believe it is

    1.6x=2.7 (x-1.8)

    1.1x=2.7*1.8

    x~4.4

    4.4*1.6

    ~7.1m
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