Oasis b is 25 km due east of oasis

a. starting from oasis a, a camel walks 24 km in a direction 20° south of east and then walks 7.0 km due north. how far is the camel then from oasis b?

Imagining a Cartesian coordinate plane, let A be at 0,0 and B be at 25,0

The camel first walks 24cos20° in the x direction and - 24sin20° in the y direction. This puts him at x = 22.55, y = - 8.21

He then increases his y value by 7 so:

y = - 8.21 + 7 = - 1.21

Ergo, the camel's distance from B is

D = √ ((25-22.55) ² + (-1.21-0) ²) = 2.73 km