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An object is dropped from a height of 75.0 m above ground level. (a) determine the distance traveled during the first second.

Answers (1)
  1. Maraki
    The relevant formula we can use in this case would be:

    h = v0 t + 0.5 g t^2

    where,

    h = height or distance travelled

    v0 = initial velocity = 0 since it was dropped

    t = time = 1 seconds

    g = 9.8 m/s^2

    So calculating for height h:

    h = 0 + 0.5 * 9.8 m/s^2 * (1 s) ^2

    h = 4.9 meters
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