A car traveling at 34 m/s runs out of gas while traveling up a 5.0 â slope. how far will it coast before starting to roll back down?

Angle = 5°

Acceleration = a = g x Sin (θ) where g = 9.8m/s² = 9.8*Sin (6) = 0.854 m/s ²,

As coasting comes to a stop:

v = a x t = 0

t = v/a = 34/0.854 = 39.8 seconds

The distance traveled is:

d = (vf-vi) t - (1/2) at ² = 34 x 39.8 - (1/2) (0.854) (39.8) ² = 1353.2 - 676.4

= 676.8 m