A horizontal force of 175 n pushes a 17 kg block up a frictionless incline that makes an angle of 43° with the horizontal. (a) what is the normal force that the incline exerts on the block?

The normal force that the incline exerts on the block will be equal in magnitude to the sum of the following: 1. the component of weight directed into the incline 2. the component of the force pressing the block against the incline normal force = mg cos (43) + F sin (43) normal force = (17 kg) (9.80 m/s^2) cos (43) + 175 N sin (43) normal force = 241 N The magnitude of the normal force that the incline exerts on the block is 241 N