After an average acceleration of 3.95 m/s2 during 2.25 s, a car reaches a velocity of 15.3 m/s. find the car/'s initial velocity.

Since,

We have avg. acceleration it can be put in place of accelaration in the given time period.

v=15.3m/s

a = 3.95m/s

t = 2.25 s

by using,

a = (v-u) / t

3.95 = (15.3-u) / 2.25

(3.95*2.25) - 15.3 = - u

8.8875-15.3 = - u

-6.4125 = - u

⇒ u = 6.4125 m/s