How much power does it take to lift a 4500kg elevator 25m up a shaft in 29s?

Correct answer: P = 38,793.1 W = 38.7 kW

Explanation:

Power is calculated according to the following formula:

P = A / t

where A is the work performed and t the elapsed time

work is a measure of changing energy

A = ΔEp = m · g · h we will take that g = 10 m/s

A = 4,500 · 10 · 25 = 1,125,000 J

P = 1,125,000 / 29 = 38,793.1 W = 38.7 kW

P = 38,793.1 W = 38.7 kW

God is with you!