Ask Question
5 August, 16:09

Over a short interval the coordinate of a car in the meters isgiven by x (t) = 27t - 4.0 t3 where time t is in seconds, at the end of 1.0s the acceleration of the car is

1. 27 m/s2

2. 4.0 m/s2

3. - 4.0 m/s2

4. - 12 m/s2

5. - 24 m/s2

+3
Answers (1)
  1. 5 August, 16:27
    0
    5. - 24 m/s²

    Explanation:

    Acceleration: This can be defined as the rate of change of velocity.

    The S. I unit of acceleration is m/s².

    mathematically,

    a = dv/dt ... Equation 1

    Where a = acceleration, dv/dt = is the differentiation of velocity with respect to time.

    But

    v = dx (t) / dt

    Where,

    x (t) = 27t-4.0t³ ... Equation 2

    Therefore, differentiating equation 2 with respect to time.

    v = dx (t) / dt = 27-12t² ... Equation 3.

    Also differentiating equation 3 with respect to time,

    a = dv/dt = - 24t

    a = - 24t ... Equation 4

    from the question,

    At the end of 1.0 s,

    a = - 24 (1)

    a = - 24 m/s².

    Thus the acceleration = - 24 m/s²

    The right option is 5. - 24 m/s²
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Over a short interval the coordinate of a car in the meters isgiven by x (t) = 27t - 4.0 t3 where time t is in seconds, at the end of 1.0s ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers