Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters along the incline, how much work will he do on the box?

A.

5.2 * 102 joules

B.

6.0 * 102 joules

C.

-5.2 * 102 joules

D.

-6.0 * 102 joules

The work done is, w = 6 x 10² J

Explanation:

Given,

The angle of the incline, ∅ = 30°

The force applied parallel to the incline, F = 60 N

The displacement caused by the force along the incline, s = 10 m

Since the force and displacement is along the incline, the angle of incline doesn't contribute to the work done.

The work done by the force is given by the relation,

W = F · S

= 60 N x 10 m

= 600 J

Hence, the work done by Roger pushing the box is, W = 600 J