An acorn falls from a branch located 9.8 m above the ground. After 1 s of falling, the acorn's velocity will be 9.8 m/s downward. Why hasn't the acorn hit the ground?

The acorn hasn't hit the ground because it only falsl half of the branch distance from the ground

Explanation:

given information:

h = 9.8

t = 1 s

g = 9.8

the average speed

v = 1/2 gt²

= 1/2 (9.8) (1) ²

= 4.8 m/s

the distance in 1s

h = v t

= 4.8 (1)

= 4.8 m

the acorn hasn't hit the ground because it only falsl half of the branch distance from the ground

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