A fly undergoes a displacement of - 5.80m while accelerating at - 1.33m/s^2 for 4.22 s what was the initial velocity of the fly?

1.43 m/s

Explanation:

From the question, we have;

Displacement, s = - 5.80 m Acceleration, a = - 1.33 m/s² Time, t is 4.22 s

We are required to calculate the initial velocity, u of the fly;

We are going to use the suitable equation of linear motion. In this case, the suitable equation is;

S = 0.5at² + ut, where S is the displacement. a is the acceleration, u is the initial velocity and t is time

Putting the values of the variables, we get;

-5.80 m = (0.5 * (-1.33 m/s²) * (4.22 s) ²) + (u*4.22 s)

-5.80 m = - 11.8426 + 4.22u

4.22u = 6.0426

u = 1.432 m/s

= 1.43 m/s

Therefore, the initial velocity of the fly is 1.43 m/s