A conductor of length 0.8 m carrying a current of 2.5 A is kept in a magnetic field of 0.6 Tesla. What is the magnitude of the force experienced by the conductor if it is inclined at an angle 30° to the direction of the magnetic field?

Answer: 0.6N

Explanation:

To calculate the magnitude of the force experienced by the conductor, we use the formulae

F = BILsintheta

Where B is the magnetic field

I is the current

L is the length

theta is the angle that the conductor made with the magnetic field

Substituting the given parameters into the formulae,

F = (0.6 * 2.5 * 0.8) sin30°

F = 0.6N