It takes 11.2 kJ of energy to raise the temperature of 145 g of benzene from 23.0°C to 68.0°C. What is the specific heat of benzene?

1716.475 J/kg.°C.

Explanation:

Specific Heat capacity is given as

Q = cm (t₂-t₁) ... Equation 1

Where Q = quantity of heat, c = specif heat of benzene, m = mass of benzene, t₁ = initial temperature, t₂ = final temperature.

Make c the subject of the equation,

c = Q/m (t₂-t₁) ... Equation 2

Given: Q = 11.2 kJ = 11200 J m = 145 g = 0.145 kg, t₂ = 68.0°C, t₁ = 23.0°C

Substitute into equation 2.

c = 11200/[0.145 (68-23) ]

c = 11200/6.525

c = 1716.475 J/kg.°C.

Hence the specific heat of benzene = 1716.475 J/kg.°C.