Two facing surfaces of two large parallel conducting plates separated by 7.0 cm have uniform surface charge densities such that are equal in magnitude but opposite in sign. The difference in potential between the plates is 560 V. Is the positive or the negative plate at the higher potential?

Given that,

The distance between two conducting plates is 7 cm.

The difference in potential between the plates is 560 V.

To find,

We need to tell is the positive or the negative plate at the higher potential?

Solution,

We know that the electric potential is defined as the work done in moving a test charge from one position to another. So, the positive plate is always at the higher potential.

Hence, this is the required solution.