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18 July, 02:23

Calculate the maximum force that a 0.2-in. diameter rod of Al2O3, having a yield strength of 35,000 psi, can withstand with no plastic deformation. Express your answer in both lbs and N.

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  1. 18 July, 03:30
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    F=бА

    Explanation:

    dа ta:

    б=35,000 psi

    А=0.2

    solution:

    put values in formula:

    = (35,000) (π/4) (0.2) ²

    =1100lb (in pounds)

    for newton N

    = (1100) (4.48N/lb)

    =4891N
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