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27 March, 20:13

While riding on an elevator descending with a constant speed of 2.7 m/s, you accidentally drop a book from under your arm. How long does it take for the book to reach the elevator floor, 1.0 m below your arm?

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  1. 27 March, 21:48
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    0.45 s.

    Explanation:

    From Newton's equation of motion,

    s = ut + 1/2gt² ... Equation 1

    Where s = distance, u = initial velocity, a = acceleration, t = time

    Given: s = 1.0 m, u = 0 m/s (dropped from height), g = 9.81 m/s²

    Substituting into equation 1,

    1 = 0 (t) + 1/29.81 (t²)

    1 = 9.81t²/2

    2 = 9.81t²

    t² = 2/9.81

    t² = 0.204

    t = √ (0.204)

    t = 0.45 s.

    Hence it takes 0.45 s for the book to reach the elevator floor.
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