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12 October, 17:21

Calculate the magnitude of q for a system that does 603000 kJ of work on its surroundings and for which the change in total internal energy is - 1.80 * 104 kJ.

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  1. 12 October, 17:35
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    Q=585000 kJ

    Explanation:

    Given Data

    W (Work) = 603000 kJ

    ΔU (Change in total internal energy) = -1.80*10⁴ kJ

    Q (Heat Supplied) = ?

    Solution

    First Law of thermodynamic:

    The first law of thermodynamics states that energy can neither be created nor destroyed, but only converted between various forms. For a closed system, we may write the change in internal energy as:

    ΔU=Q-W

    Q=ΔU+W

    Q = - 1.80*10⁴+603000

    Q = 585000 kJ
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