Four objects are situated along the y axis as follows: a 1.93-kg object is at + 2.93 m, a 3.06-kg object is at + 2.58 m, a 2.41-kg object is at the origin, and a 3.96-kg object is at - 0.498 m. Where is the center of mass of these objects?

Answer: x, y (0, 1)

Explanation:

the X coordinate of the center mass is

X (c) = Σm (i) * x (i) / Σx (i)

X (c) = (0 + 0 + 0 + 0) / (1.93 + 3.06 + 2.41 + 3.96)

X (c) = 0 / 11.36

X (c) = 0

The y coordinate of the center mass is

Y (c) = Σm (i) y (i) / Σm (i)

Y (c) = [ (1.93) (2.93) + (3.06) (2.58) + (2.41) (0) + (3.96) (-0.498) ] / (1.93 + 3.06 + 2.41 + 3.96)

Y (c) = (5.6549 + 7.8948 + 0 - 1.97208) / 11.36

Y (c) = 11.57762 / 11.36

Y (c) = 1.02

Therefore, the center of masses is at x, y (0, 1)