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1 July, 23:09

A sled is on an icy (frictionless) slope that is 30° above the horizontal. When a 40-N force, parallel to the incline and directed up the incline, is applied to the sled, the acceleration of the sled is 2.0 m/s 2, down the incline ... The mass of the sled is:

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  1. 2 July, 00:35
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    Answer: 5.8kg

    Explanation:

    F - mg sinΦ = ma

    Given that

    M=?

    g = 9.8

    Φ = 30

    a = 2

    F = 40 then

    40 - 9.8 * m * sin 30 = 2 * m

    40 = 2 * m + 9.8 * m * sin 30

    40 = (2 + 9.8 * sin 30) m

    m = 40 / (2 + 9.8 * 0.5)

    m = 40 / (2 + 4.9)

    m = 40 / 6.9

    m = 5.797kg

    m = 5.8kg
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