A box is dropped onto a conveyor belt moving at 3.40 m/s. If the coefficient of friction between the box and the belt is 0.270, how long will it take before the box moves without slipping

Answer:t=1.28 seconds

Explanation:

The newton law of motion said

Force = mass * acceleration

The friction force said

a = u. g

a = 0.270 * 9.81

a=2.65m/s^2

Now applied the kinematics equation

v = u + at

v=3.40 and u = 0

Now

t = 3.40/2.65

t=1.28 seconds