You observe a hockey puck of mass 0.12 kg, traveling across the ice at speed 18.3 m/sec. The interaction of the puck and the ice results in a frictional force on the puck, f = 0.14 N.

Calculate: the stopping distance for this puck.

First you must calculate the acceleration of the puck using F=ma. The force F is negative. 14 N, the frictional force, and the mass is. 12 kg. Solving for a=F/m, we get a=-1.17 m/s^2. Now we use a kinematic equation. vf^2=vi^2 + 2ax. We need to solve for x. We know the final speed vf is 0 because we are finding the stopping distance. Initial velocity vi is given as 18.3 m/s. We just found acceleration a is - 1.17 m/s^2. Now we need to solve for displacement x, which is the answer to the question. Plugging in the appropriate values to the kinematic equation gives us 0=18.3^2 - 2 (1.17) x. 2 (1.17) x=18.3^2. x=143 m