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11 February, 18:58

A ball is thrown into the air with an initial velocity of 15 m/s, how high into the air does the ball travel?

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  1. 11 February, 22:09
    0
    11.25m

    Explanation:

    vf^2=vi^2+2ad

    0^2=15^2+2 * (-10) d

    0=225+-20d (remove 225 by doing the opposite operation)

    -225:-20=-20d:-20 (remove - 20 by dividing by itself)

    11.25 = d (the answer becomes this)
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